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May 7, 2014 at 16:53 comment added Barrett I see. Thanks. I will look into it.
May 6, 2014 at 20:01 comment added littleO Let's assume $A$ has full rank and $m < n$, and that the primal optimal value is finite. You could let $\Phi(u,p) = \langle c, u \rangle + I_K(u) + I_0(Au - b - p)$, where $I_K$ is the indicator function of $K$, and $I_0$ is the indicator function of $\{0\}$. I'm not sure about this, but I'm guessing that if you assume there exists $u_0$ in the interior of $K$ such that $A u_0 = b$, then it will follow that $h$ is continuous at $0$. This is similar to Slater's condition. I don't think the argument I posted applies exactly, but perhaps something similar would work.
May 6, 2014 at 19:55 comment added littleO But, $\Phi$ is allowed to take on the value $+\infty$, to enforce constraints. So I think it will be possible to put your problem into this framework.
May 6, 2014 at 18:35 comment added Barrett This is the sort of result I am interested in, but I think I don't think I can directly apply this result because the function is being optimized over the whole vector space V, so it avoids the issue of having constraints that must be satisfied.
May 6, 2014 at 9:20 review First posts
May 6, 2014 at 9:22
May 6, 2014 at 9:04 history answered littleO CC BY-SA 3.0