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Feb 26, 2010 at 15:07 answer added Georges Elencwajg timeline score: 2
Feb 26, 2010 at 14:46 comment added Kevin Buzzard Touch\'e ;-)
Feb 26, 2010 at 14:39 comment added Mariano Suárez-Álvarez $E$ can coincide with $E'$.
Feb 26, 2010 at 14:33 comment added Kevin Buzzard I always thought that the only subextension of Q(2^{1/4})/Q was Q(2^{1/2}). Am I wrong?
Feb 26, 2010 at 14:24 history edited Mariano Suárez-Álvarez CC BY-SA 2.5
added 10 characters in body
Feb 26, 2010 at 13:48 history asked Mariano Suárez-Álvarez CC BY-SA 2.5