Timeline for For which cardinal numbers $\kappa$ is it consistent with ZFC that $\kappa^{\mathrm{cf}(\kappa)} < \kappa^\kappa$?

6 events

when toggle format	what		by	license	comment
May 4, 2014 at 21:59	vote	accept	goblin GONE
May 4, 2014 at 12:42	answer	added	Goldstern		timeline score: 5
May 3, 2014 at 1:16	answer	added	Monroe Eskew		timeline score: 7
May 2, 2014 at 5:49	comment	added	Andrés E. Caicedo		On the other hand, we can have $2^{\aleph_0}=\aleph_1$ and $2^{\aleph_1}=\aleph_{\omega_4}$, but the first assumption already implies (by Shelah's pcf results) that $(\aleph_\omega)^{\aleph_0}<\aleph_{\omega_4}\le 2^{\aleph_\omega}$.
May 2, 2014 at 5:42	comment	added	Andrés E. Caicedo		$\kappa$ cannot be strong limit (which is why $\beth_\omega$ does not have the property).
May 2, 2014 at 5:01	history	asked	goblin GONE	CC BY-SA 3.0