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May 3, 2014 at 6:16 answer added Seva timeline score: 2
May 1, 2014 at 22:49 answer added user50282 timeline score: 9
May 1, 2014 at 14:39 comment added Seva How about fixing a non-zero element $g\in{\mathbb Z}_2^n$ and flipping a coin for each pair of elements that add up to $g$ to choose one for your set $X$? You will get a set of density $\alpha=1/2$ with $g\notin 2X$, and this set will typically be uniformly distributed in subspaces of co-dimension $1$.
May 1, 2014 at 13:54 history asked Peter Nelson CC BY-SA 3.0