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May 1, 2014 at 10:56 comment added Cusp Exactly. That's what I have realized from your comment. I was actually missing this point. Thanks again.
May 1, 2014 at 10:54 comment added Sam Nead You have to use some geometric notion to track projections to annular domains, because annuli don't have enough topology.
May 1, 2014 at 10:54 comment added Cusp Its okay. I knew that result.
May 1, 2014 at 10:53 comment added Sam Nead Perhaps I should have said "It is a non-trivial exercise..."
May 1, 2014 at 10:53 comment added Cusp Again thanks. Actually I was trying to understand this from a complete topological background, so I was trying to avoid any use of geometry.
May 1, 2014 at 10:47 comment added Sam Nead You can do things this way. However, taking the Gromov closure only requires that the metric space in question be $\delta$-hyperbolic. It is an exercise to check that for any metric $\rho$ on $S$ (with $\chi(S) < 0$) the annular cover is $\delta$-hyperbolic. (However, it is true that $\delta$ depends $\rho$.)
May 1, 2014 at 10:43 vote accept Cusp
May 1, 2014 at 10:42 comment added Cusp Thank you very much for the clarification. But I am still confused about the third part. The Gromov clouser requires the cover to have a negatively curved metric right! So are we considering $\bar{Y}$ as a quotient of $\mathbb{H}^2?$ because then it is same as considering a hyperbolic metric in $S$.
May 1, 2014 at 10:24 history answered Sam Nead CC BY-SA 3.0