Skip to main content
4 events
when toggle format what by license comment
Apr 28, 2014 at 20:09 answer added Joel David Hamkins timeline score: 4
Apr 28, 2014 at 18:54 comment added Feldmann Denis Well, if I have a proof in ZFC that there exist k such that f(k)=0 (where f is recursive),I have usually no way to exhibit such a k (so long as I have no bound for it). But in the particular case of P, I would suspect an explicit bound exists (but it should be much higher than $10^{10^{100}}$)
Apr 28, 2014 at 18:26 comment added Joel David Hamkins Regarding (c), what would it mean for a particular natural number k to not be computable? Every natural number is computable.
Apr 28, 2014 at 18:15 history asked Feldmann Denis CC BY-SA 3.0