Timeline for Maximal number of antichains of a connected poset
Current License: CC BY-SA 3.0
8 events
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Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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May 5, 2014 at 17:45 | comment | added | Michał Kukieła | @Seb Destercke: Of course you are right. I corrected the proof, hopefully without introducing new mistakes. However I feel the question deserves a more elegant answer. | |
May 5, 2014 at 17:43 | history | edited | Michał Kukieła | CC BY-SA 3.0 |
corrected proof
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Apr 26, 2014 at 8:24 | comment | added | Seb Destercke | Thank you for the nice proof, yet if I am not wrong for the two disjoint 2-element chains we have $$3\cdot 3 \cdot 2^{n-4}=(2^3+1)\cdot 2^{n-4}=2^{n-1}+2^{n-4} > 2^{n-1}+1$$ | |
Apr 25, 2014 at 16:12 | comment | added | Emil Jeřábek | @VinceVatter: $2^{2-1}+2\ne3$. Anyway, there are $2^{n-1}$ antichains that are subsets of the nonminimal elements (including the empty antichain), and one antichain consisting of the minimal element. | |
Apr 25, 2014 at 12:31 | vote | accept | Seb Destercke | ||
Apr 25, 2014 at 10:20 | history | answered | Michał Kukieła | CC BY-SA 3.0 |