Timeline for How do I prove a matrix A is self adjoint to an inner product? . [closed]
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Apr 24, 2014 at 7:05 | history | closed |
Andrés E. Caicedo Nik Weaver Jeremy Rickard Seva David Roberts♦ |
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| Apr 24, 2014 at 7:01 | comment | added | squibben | I have the following statements (1) since b is symmetric B=B^t also if BA is symmetric then BA=(BA)^t therefore BA=(BA)^t=B^t.A^t=B^t.A . also I have A is a linear map such that A:r^n->r^n and A* is a linear map such that A*:r^n->r^n now since A=A* A is self adjoint. but im not sure why it is self adjoint wrt the B-inner-product space ? | |
| Apr 24, 2014 at 6:50 | comment | added | squibben | Im unsure of how you are supposed to prove something is self adjoint with respect to something else ? | |
| Apr 24, 2014 at 6:48 | comment | added | Name | Homework needs work. | |
| S Apr 24, 2014 at 6:41 | history | suggested | William Chang | CC BY-SA 3.0 |
latex and grammar fixes
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| Apr 24, 2014 at 6:37 | review | Suggested edits | |||
| S Apr 24, 2014 at 6:41 | |||||
| S Apr 24, 2014 at 6:29 | review | First posts | |||
| Apr 24, 2014 at 9:25 | |||||
| S Apr 24, 2014 at 6:29 | review | Close votes | |||
| Apr 24, 2014 at 7:06 | |||||
| Apr 24, 2014 at 6:10 | history | asked | squibben | CC BY-SA 3.0 |