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Jun 1, 2014 at 21:38 answer added ACL timeline score: 8
Jun 1, 2014 at 19:47 history edited Michael Hardy CC BY-SA 3.0
added 50 characters in body; edited title
Jun 1, 2014 at 12:23 answer added Testcase timeline score: 33
May 31, 2014 at 22:19 vote accept William Chang
May 30, 2014 at 19:06 answer added David E Speyer timeline score: 60
Apr 23, 2014 at 19:07 vote accept William Chang
May 31, 2014 at 22:19
Apr 23, 2014 at 15:08 answer added so-called friend Don timeline score: 41
S Apr 23, 2014 at 13:40 history suggested GNiklasch CC BY-SA 3.0
rearranged first chain of equalities and added missing factor in one denominator
Apr 23, 2014 at 13:18 review Suggested edits
S Apr 23, 2014 at 13:40
Apr 23, 2014 at 13:00 history edited Gerry Myerson CC BY-SA 3.0
reworded a little to remove "infinite primes"
Apr 23, 2014 at 11:48 comment added KConrad The product seems "simple" only because the expression was rigged to remove the powers of $\pi$ in $\zeta(2)$ and $\zeta(4)$. Also, your factorization with terms $(p-1)/(p\pm i)$ is into two products that are each divergent, though that wouldn't stop Ramanujan.
Apr 23, 2014 at 11:27 comment added Dietrich Burde The result is attributed to Ramanujan (1913-1914), who may have used other methods (like hypergeometric series, continued fractions etc.). A reference is Le Lionnais, F. Les nombres remarquables. Paris: Hermann, p. 46, 1983.
Apr 23, 2014 at 6:54 review First posts
Apr 23, 2014 at 7:32
Apr 23, 2014 at 6:37 history asked William Chang CC BY-SA 3.0