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Apr 24, 2014 at 11:06 comment added Piero D'Ancona I think it's hopeless to look for a characterization in terms of norms or asymptotic properties; these would not distinguish small perturbations of a characteristic function. Maybe you could use the fact that they coincide with their square, so that the transform $f$ satisfies $f*f=f$
Apr 24, 2014 at 1:07 answer added guest007 timeline score: 1
Apr 23, 2014 at 18:30 answer added Joni Teräväinen timeline score: 7
Apr 22, 2014 at 23:30 history edited Joni Teräväinen CC BY-SA 3.0
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Apr 22, 2014 at 23:22 comment added Joni Teräväinen By regularity of the Fourier transform, I meant both its decay and smoothness. If these Fourier transforms are always entire, then I just mean decay, but if we for example take a Cantor-type set extending to infinity with positive finite measure, I don't see directly why the Fourier transform should be analytic.
Apr 22, 2014 at 23:05 comment added Christian Remling I don't think we expect the regularity of $A$ to affect the REGULARITY of $\widehat{\chi_A}$ (rather, regularity/smoothness <-> decay is the received wisdom).
Apr 22, 2014 at 18:52 history asked Joni Teräväinen CC BY-SA 3.0