Timeline for Does there exist a base $\{e_j\}_{j\geq 1}$ of $H(\Omega)$ such that $\{e_j\}_{j\geq 1}$ is linearly independent in $L^2(\omega)^d$?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
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| Apr 24, 2014 at 13:00 | comment | added | Michael Renardy | You can use the Stokes operator with slip conditions instead. | |
| Apr 23, 2014 at 16:55 | comment | added | Tran Lam | Thank you for your suggest. Can you explain the eigenfunctions of the Stokes operator. In my knowledge, the eigenfunctions of the stokes operator have to take with the Dirichlet boundary condition!? | |
| Apr 22, 2014 at 17:57 | comment | added | Michael Renardy | Take the eigenfunctions of the Stokes operator. They are analytic in $\Omega$, so if any linear combination vanishes in $\omega$, then it also vanishes in $\Omega$. | |
| Apr 22, 2014 at 15:34 | review | First posts | |||
| Apr 22, 2014 at 15:36 | |||||
| Apr 22, 2014 at 15:17 | history | asked | Tran Lam | CC BY-SA 3.0 |