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Apr 25, 2014 at 8:44 vote accept Libli
Apr 24, 2014 at 21:32 answer added Cinzia Casagrande timeline score: 5
Apr 21, 2014 at 16:15 history edited Libli CC BY-SA 3.0
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Apr 21, 2014 at 10:15 comment added abx Not birational, K-equivalent! All these varieties are rational, hence birational to each other.
Apr 21, 2014 at 10:08 history edited Libli CC BY-SA 3.0
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Apr 21, 2014 at 2:23 comment added Lev Borisov I don't see any obvious maps to a $\mathbb P^1$ here. It would be more reasonable to ask whether this variety is a $K$-equivalent to a $\mathbb P^2$-bundle over $(\mathbb P^1)^3$.
Apr 20, 2014 at 22:04 answer added Jason Starr timeline score: 1
Apr 20, 2014 at 20:58 history asked Libli CC BY-SA 3.0