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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Apr 18, 2014 at 23:58 vote accept Khalid Bou-Rabee
Apr 18, 2014 at 17:12 answer added Misha timeline score: 11
Apr 18, 2014 at 3:32 comment added Igor Rivin And another edit...
Apr 18, 2014 at 3:15 comment added Igor Rivin See the edit to my answer.
Apr 17, 2014 at 22:12 comment added YCor I don't know, there are plenty of possible variations. Still this sounds likely: I'd guess that there exists a Zariski dense subgroup of infinite index containing the integral Heisenberg group, and thus not isomorphic to a subgroup of a RAAG.
Apr 17, 2014 at 20:52 answer added Igor Rivin timeline score: 7
Apr 17, 2014 at 20:25 comment added Khalid Bou-Rabee That's neat. Do you have any feeling on whether there might be an example that is not a right-angled Artin group?
Apr 17, 2014 at 20:18 comment added YCor It's very likely that $SL_3(\mathbf{Z})$ contains free products such as $\mathbf{Z}^2\ast\mathbf{Z}$ (necessarily Zariski dense). Anyway the construction of such groups probably requires a little effort.
Apr 17, 2014 at 19:58 history asked Khalid Bou-Rabee CC BY-SA 3.0