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Apr 18, 2014 at 21:27 comment added Joni Teräväinen True, $p_{n+2}$ is a better limit for $|d|$ as everything works in the same way. I fixed it now.
Apr 18, 2014 at 21:25 history edited Joni Teräväinen CC BY-SA 3.0
minor edit
Apr 18, 2014 at 20:55 comment added The Masked Avenger In the definition of $C_n$, which you got mostly correct, I originally intended $|d|$ to be a power of 2 less than $p_{n+1}$, and now I want it less than $p_{n+2}$. This does not change the fundamental character of your answers though, and I appreciate your making precise the definition of $C_n$, as well as your answers.
Apr 16, 2014 at 15:03 history answered Joni Teräväinen CC BY-SA 3.0