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Feb 2, 2019 at 9:52 vote accept B . O
Apr 15, 2014 at 21:11 comment added B . O Probably, the value changed very rapidly by $\omega(n)$ and $\omega(n)−1$ as $a$ grows up. And it seems to need some sharp techniques for deciding between them for given certain $k$, because the estimation be smaller while the weight(changeable values) bigger. I will have a try with your advise, Thanks!
Apr 15, 2014 at 20:17 comment added Greg Martin It changes it, yes, but probably in a way that can be handled. After all, $\omega_{\sqrt x}(n)$ is either $\omega(n)$ or $\omega(n)-1$ in a predictable way.
Apr 15, 2014 at 19:44 comment added B . O Thanks for your answer, but I've obtained that representation and that's the reason of why I called it 'weight'. I think that the $k$ of $\omega_k$ changes the estimation of the arithmetic summation.
Apr 15, 2014 at 19:11 history answered Greg Martin CC BY-SA 3.0