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Apr 14, 2014 at 17:01 comment added Gaurav @Bati No local times can be calculated it seems..... I wanted to know number of times
Apr 14, 2014 at 16:28 comment added Gaurav How do I prove that it hits immediately infinitely many times just after hitting once?
Apr 14, 2014 at 13:25 comment added Nate Eldredge This assumes that by "constrained" you mean "reflected at both boundaries". If you mean "conditioned to remain in the interval" then the answer is 0.
Apr 14, 2014 at 13:21 comment added Nate Eldredge As soon as it hits the boundary once, it immediately hits it infinitely many more times. So either the answer is just infinity or "how many" is not the right question.
Apr 14, 2014 at 12:40 comment added Bati Perhaps local times?
S Apr 14, 2014 at 12:04 history suggested Davide Giraudo
Added two tags.
Apr 14, 2014 at 12:02 review Suggested edits
S Apr 14, 2014 at 12:04
Apr 14, 2014 at 9:27 review First posts
Apr 14, 2014 at 9:30
Apr 14, 2014 at 9:27 history edited Gaurav CC BY-SA 3.0
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Apr 14, 2014 at 9:19 history edited Gaurav CC BY-SA 3.0
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Apr 14, 2014 at 9:12 history asked Gaurav CC BY-SA 3.0