Timeline for Tensor products of two irreducible representations of reductive groups and their inclusions
Current License: CC BY-SA 3.0
5 events
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Jul 12, 2014 at 15:19 | comment | added | user44191 | Ah, sorry; I think I missed the tiny asterisk in the second subscript. | |
Jul 12, 2014 at 15:00 | comment | added | Jim Humphreys | My last paragraph is accurate, but I was simplifying the original formulation by replacing $\mu^*$ by $\mu$. Anyway, Victor's answer and the fuller version I got from Kumar extract the answers to (1) and (2) mainly from PRV. For (2) it's probably not strictly necessary to interpret the modules as global sections of line bundles, but for this version the best convention is to use $B^-$ rather than $B$. Algebraic group people like Andersen and Jantzen write things this way. Mixing $B, B^-$ gets confusing. | |
Jul 11, 2014 at 17:33 | comment | added | user44191 | I don't think that's quite accurate; it should be that $V_\lambda \otimes V_{\mu'}$ is included in $V_{\lambda + \nu} \otimes V_{\mu' + (-w_0 \nu)}$, if you are making the substitution $\mu' = -w_0 \mu$. Consider, for example, the case of $SL_3$ with $\lambda = \mu = 0, \nu = \omega$; clearly, whenever $\lambda = \mu = 0$, you get the natural inclusion of $\mathbb{C}$ into $V_\nu \otimes V_\nu^*$, but there is no inclusion of $\mathbb{C}$ into $V_\nu \otimes V_\nu$. | |
Apr 12, 2014 at 18:29 | history | edited | Jim Humphreys | CC BY-SA 3.0 |
added 108 characters in body; Post Made Community Wiki
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Apr 12, 2014 at 17:46 | history | answered | Jim Humphreys | CC BY-SA 3.0 |