Timeline for Powers of $2$ and the products of initial odd primes
Current License: CC BY-SA 4.0
15 events
when toggle format | what | by | license | comment | |
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Apr 2, 2023 at 5:56 | history | edited | Bjørn Kjos-Hanssen | CC BY-SA 4.0 |
added 1 character in body
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Apr 2, 2023 at 5:56 | comment | added | Bjørn Kjos-Hanssen | There is also $(d p)=(2 3) $ :) | |
Mar 29, 2023 at 11:12 | review | Suggested edits | |||
Mar 29, 2023 at 13:16 | |||||
Mar 29, 2023 at 9:53 | answer | added | user178594 | timeline score: 0 | |
Apr 12, 2014 at 19:07 | comment | added | Włodzimierz Holsztyński | @TMA, if you posted your question about $f(p)$, I would welcome it (while "similar interesting" seems vague and too encompassing). | |
Apr 12, 2014 at 12:20 | vote | accept | Włodzimierz Holsztyński | ||
Apr 12, 2014 at 11:37 | answer | added | user46855 | timeline score: 3 | |
Apr 12, 2014 at 9:50 | answer | added | Aravind | timeline score: 9 | |
Apr 12, 2014 at 8:17 | history | edited | Włodzimierz Holsztyński | CC BY-SA 3.0 |
A more complete statement (within the acknowledgement).
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Apr 12, 2014 at 7:52 | history | edited | Włodzimierz Holsztyński | CC BY-SA 3.0 |
Upper case
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Apr 12, 2014 at 5:36 | history | edited | Włodzimierz Holsztyński | CC BY-SA 3.0 |
better grammar, I guess.
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Apr 12, 2014 at 5:26 | comment | added | The Masked Avenger | You might prefer the following. Let f(p) be the power of 2 that divides precisely (O_p)^2 - 1. Is f(p) unbounded as a function of p? Similar interesting questions around f(p) could be posed. | |
Apr 12, 2014 at 5:26 | history | edited | Włodzimierz Holsztyński | CC BY-SA 3.0 |
Motivation
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Apr 12, 2014 at 5:19 | comment | added | The Masked Avenger | Likely yes. For large p Fermat's little theorem will determine the character of the primes dividing 2^p +- 1. You can check this out using Carmichael's tables to shoa no other small solutions. | |
Apr 12, 2014 at 5:11 | history | asked | Włodzimierz Holsztyński | CC BY-SA 3.0 |