Timeline for How can I solve a cubic equation in a finite field with characteristic 2?
Current License: CC BY-SA 3.0
3 events
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| Apr 12, 2014 at 4:53 | comment | added | user13113 | If $q = 0$, then you have $2^d$ solutions. Of course, you could divide by $z$ rather than multiply by $z$ in that case. | |
| Apr 12, 2014 at 2:48 | comment | added | P Vanchinathan | Nice idea; it is amazing that linear algebra can be exploited to solve a cubic equation. Are there any similar tricks in other characteristics , especially 0? | |
| Apr 12, 2014 at 0:20 | history | answered | Noam D. Elkies | CC BY-SA 3.0 |