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S May 16, 2014 at 19:25 history suggested Jyrki Lahtonen CC BY-SA 3.0
TeX bug - sorry about not catching it right away.
May 16, 2014 at 19:23 review Suggested edits
S May 16, 2014 at 19:25
S May 16, 2014 at 19:19 history suggested Jyrki Lahtonen CC BY-SA 3.0
Some TeXifying
May 16, 2014 at 19:17 review Suggested edits
S May 16, 2014 at 19:19
Apr 13, 2014 at 1:39 comment added Gerry Myerson In the comment about 08, are you using the symbol $a$ to mean two different things, a "prime element" and the coefficient of $x^2$?
Apr 12, 2014 at 4:56 comment added user13113 IIRC, you can repeat the derivation of the cubic formula.
Apr 12, 2014 at 0:20 answer added Noam D. Elkies timeline score: 28
Apr 11, 2014 at 23:19 comment added Dimitri @Felipe: You are right, that was my mistake. This answers my question. Thank you very much.
Apr 11, 2014 at 23:19 review Close votes
Apr 12, 2014 at 10:32
Apr 11, 2014 at 23:04 review First posts
Apr 11, 2014 at 23:15
Apr 11, 2014 at 23:03 comment added Dimitri Yes certainly it is possible. The point of the example was to demonstrate that there are cubic equations that have solutions for which (a^2 + b) does not have a sq root. The 08 is the hex representation of a GF(2^5) element - in binary form it would be '01000', equal to a^3, a being the prime element. This equation does have (at least) one root: For x=10 ('1000' = a^4) it becomes zero, yet (a^2+b) which is equal to b (=08=a^3) in this case does not have a square root because it equals an odd power of a.
Apr 11, 2014 at 23:01 comment added Felipe Voloch Every element has a square root in a finite field of even order.
Apr 11, 2014 at 22:56 comment added Gerry Myerson I don't know what 08 is (a coefficient in your example cubic). But it's possible that a cubic has no solution in a given finite field, right? Anyway, MO is for math research --- I don't see where there's a research angle to your question.
Apr 11, 2014 at 22:45 history asked Dimitri CC BY-SA 3.0