Timeline for Asymptotic expansion of the Mordell integral
Current License: CC BY-SA 3.0
7 events
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| Jul 25, 2015 at 5:47 | history | edited | მამუკა ჯიბლაძე | CC BY-SA 3.0 |
Made a piece of code from a piece of code recorded using MathJax
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| Apr 9, 2014 at 8:44 | comment | added | MHMertens | BTW, MAPLE's limit command also tells me that the limit is $0$ which would be enough for my purpose, although I don't really trust MAPLE in this since I don't know how it computes these things. | |
| Apr 9, 2014 at 8:11 | comment | added | MHMertens | There might be a tiny problem with this solution though: The Mordell integral as such is only defined for $\tau$ in the upper halfplane, in particular not in any neighbourhood of $0$. So a Taylor expansion around $0$ is not very well possible, is it? MAPLE probably doesn't care for that though... | |
| Apr 8, 2014 at 16:57 | comment | added | S. Carnahan♦ | I guess that's not bad, although $z$ really should be greater than $-1/6$. | |
| Apr 8, 2014 at 16:48 | comment | added | user64494 | The questioner assumes $z$ to be real. In this case the last integral converges for $|z|< \frac 1 3$ at least. | |
| Apr 8, 2014 at 16:38 | comment | added | S. Carnahan♦ | Does that last integral converge for arbitrary $z \in \mathbb{C}$? | |
| Apr 8, 2014 at 16:26 | history | answered | user64494 | CC BY-SA 3.0 |