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Apr 11, 2014 at 5:28 vote accept tao mei
Apr 10, 2014 at 7:52 comment added Mikael de la Salle Tao, let's continue this discussion by mail.
Apr 10, 2014 at 5:17 comment added tao mei Thanks for the comments, Yemon and Suvrit. Hi, MiKael, Thanks for the answer. I like your clever use of "the elementary inequality". Your answer implies a very interesting result (to me), see the email I am sending to you.
Apr 10, 2014 at 4:54 comment added tao mei Thanks for the comments, Yemon and Suvrit.Hi, MiKael, Thanks for the answer.
Apr 9, 2014 at 10:07 history edited Mikael de la Salle CC BY-SA 3.0
added 499 characters in body
Apr 8, 2014 at 21:17 comment added Suvrit Thanks for catching the bug; my error lay in calling $e^{4t(i+j+1)}-1$ a rank-1 matrix --- how silly can one be!
Apr 8, 2014 at 18:30 comment added Mikael de la Salle You are right. It also occured to me that my answer (and the question...) was absurd it there was an easy way to prove that $A$ is positive. And the question whether $A$ is positive is even more natural now that we known (from my complicated answer) that the trace of $A$ and its trace norm are comparable.
Apr 8, 2014 at 16:13 comment added Suvrit It the original Hankel matrix is PSD, then we'll immediately get $\|H\| \le e^{-4t} \le 1$, but I haven't checked if it is psd (but clearly my reasoning seems naive to me)..
Apr 7, 2014 at 20:42 history answered Mikael de la Salle CC BY-SA 3.0