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Aug 14, 2021 at 13:26 comment added Fabius Wiesner We can say that $\mathcal{A}(F)$ is equal to a member of $F$ OR the intersection of some members of $F$. To see why, see equation $(1)$ here. Probably that doesn't help much though.
Apr 7, 2014 at 21:03 answer added MassiveJack timeline score: 8
Apr 7, 2014 at 14:54 history edited MassiveJack CC BY-SA 3.0
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Apr 7, 2014 at 14:47 history edited MassiveJack CC BY-SA 3.0
added 19 characters in body
Apr 7, 2014 at 14:08 vote accept MassiveJack
Apr 7, 2014 at 13:49 answer added Thomas Bloom timeline score: 8
Apr 7, 2014 at 11:09 answer added Nathann Cohen timeline score: 1
Apr 7, 2014 at 10:57 review First posts
Apr 7, 2014 at 11:18
Apr 7, 2014 at 10:39 history asked MassiveJack CC BY-SA 3.0