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Apr 7, 2014 at 21:37 comment added Marty Isaacs You have probably already checked this, but Magma says that for p=3 and n=1, the groups are isomorphic.
Apr 7, 2014 at 19:15 history edited Yassine Guerboussa CC BY-SA 3.0
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Apr 7, 2014 at 19:14 comment added Yassine Guerboussa Ok, It is my mistake that I didn't noticed that $M$ is not abelian.
Apr 7, 2014 at 19:12 comment added Yassine Guerboussa @Jared: thanks for your comment; You may notice that $M$ is not abelian, so that $M \times E_n$ and $E_{n+3}$ cannot be isomorphic.
Apr 7, 2014 at 17:39 comment added Jared Perhaps I'm not understanding the question, but it seems to me that $M\times E_n\cong E_{n+3}$. Viewing $E_{n}$ as a vector space over $\mathbb{F}_p$, we then have the isomorphism of groups $\mathrm{Aut}(E_n)\cong\mathrm{GL}(n,p)$ for all $n$.
Apr 7, 2014 at 10:22 history asked Yassine Guerboussa CC BY-SA 3.0