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May 2, 2014 at 4:48 vote accept 346699
Apr 10, 2014 at 16:26 history edited 346699 CC BY-SA 3.0
added 181 characters in body
Apr 7, 2014 at 20:33 answer added Igor Khavkine timeline score: 6
Apr 7, 2014 at 19:53 answer added Yiyan timeline score: 4
Apr 7, 2014 at 15:33 answer added Otis Chodosh timeline score: 7
Apr 7, 2014 at 14:35 comment added user21349 Many gravitational-wave vacuum solution to the Einstein field equations are geodesically complete. Many exact solutions of this type are known. The standard reference for this sort of thing is Stefani, Exact Solutions of Einstein's Field Equations.
Apr 7, 2014 at 10:46 answer added José Figueroa-O'Farrill timeline score: 22
Apr 7, 2014 at 9:58 history edited 346699 CC BY-SA 3.0
added 223 characters in body; edited tags; edited title
Apr 7, 2014 at 9:50 comment added Ben McKay There is a terminological mismatch between mathematicians and physicists. Mathematicians refer to manifolds with metrics of signature $(-,+,+,+)$ (or $(1,n-1)$) as Lorentzian manifolds, and use the term Riemannian manifold for metric signature $(0,n)$. Many physicists call all signatures Riemannian, apparently.
Apr 7, 2014 at 9:31 comment added Willie Wong Riemannian manifold with sign signature $(-,+,+,+)$? Are you sure you don't want Lorentzian manifolds and the tag general-relativity? (And in that case, there's a whole book about an open set of examples.)
Apr 7, 2014 at 7:55 answer added Dietrich Burde timeline score: 6
S Apr 7, 2014 at 7:37 history suggested smyrlis CC BY-SA 3.0
Improved formulation of the question
Apr 7, 2014 at 7:33 review Suggested edits
S Apr 7, 2014 at 7:37
Apr 7, 2014 at 7:28 comment added S. Carnahan If I'm not mistaken, K3 surfaces aren't flat but have Ricci flat metrics.
S Apr 7, 2014 at 7:07 history suggested Seirios
Completed tags
Apr 7, 2014 at 7:05 review Suggested edits
S Apr 7, 2014 at 7:07
Apr 7, 2014 at 6:48 history asked 346699 CC BY-SA 3.0