Skip to main content
9 events
when toggle format what by license comment
Jan 15, 2020 at 18:05 answer added user151152 timeline score: 4
Jan 14, 2020 at 19:46 answer added user151109 timeline score: 6
Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Apr 15, 2014 at 0:08 comment added Ashutosh Here is a convoluted way of saying something about Borel sets that is independent over ZFC: If every subset of a set X of reals is (relatively) Borel then X is Borel.
Apr 9, 2014 at 0:04 vote accept Noah Schweber
Apr 7, 2014 at 23:21 answer added Asaf Karagila timeline score: 13
Apr 7, 2014 at 23:05 comment added Asaf Karagila To my knowledge it's still open, at all, if we can have a quasi-amorphous (I prefer $\aleph_1$-amorphous) set of real numbers. Not just Borel. I'm also not sure if it's consistent to have an infinite Dedekind-finite set of real numbers which cannot be mapped onto itself + 1, so I'm not even sure if we have an example for that as well.
Apr 7, 2014 at 10:36 answer added Joel David Hamkins timeline score: 8
Apr 7, 2014 at 5:46 history asked Noah Schweber CC BY-SA 3.0