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Apr 6, 2014 at 6:42 vote accept Felix Goldberg
Apr 5, 2014 at 19:42 answer added Peter Dukes timeline score: 3
Apr 5, 2014 at 7:02 comment added Felix Goldberg @PeterDukes Any $c<1$ would do for me...
Apr 4, 2014 at 19:59 comment added Peter Dukes I may not understand properly, but doesn't $c=1$ work? The goal is to get $c$ as small as possible. Two observations: (1) From simple counting, it's clear that we need $c > 1/3$. (2) If you specify your set $P \subset [v]$ ahead of time and then quantify over all STS on $[v]$, you run into counterexamples for $c$ below $1/2$.
Apr 4, 2014 at 14:37 history asked Felix Goldberg CC BY-SA 3.0