Timeline for Is this Riemann zeta function product equal to the Fourier transform of the von Mangoldt function?

5 events

when toggle format	what		by	license	comment
Apr 4, 2014 at 17:55	vote	accept	Mats Granvik
Apr 2, 2014 at 18:44	comment	added	Mats Granvik		I had an error in the summation index. k was meant to be n=scale. scale is just some large number. I might have other errors in here to. I will have a look tomorrow.
Apr 2, 2014 at 18:32	comment	added	GH from MO		I still don't understand what you talk about. The definition of $g(k)$ depends on some quantity "scale", so that quantity should also be part of the argument. But then we talk about finite series, so an exact match with a Riemann zeta-like function is unlikely. Also, there is no $f(t)$ until you define it properly (i.e. you need to show the convergence). I understand that you have some experimental observations, but you should turn it into a precise mathematical question (otherwise it is like asking someone's opinion about a painting or musical piece).
Apr 2, 2014 at 18:23	comment	added	Mats Granvik		I have tried to correct the definitions in the question. $f(t)$ is a function of the imaginary (is that right?) variable $t$. The convergence of $f(t)$ I don't know anything about. What I do know is that by plotting the function for nn = 10, nn = 50, nn = 300, nn = 5000 there isn't much difference in the shape and position of the graph plotted.
Apr 2, 2014 at 14:00	history	answered	GH from MO	CC BY-SA 3.0