Skip to main content
6 events
when toggle format what by license comment
Apr 2, 2014 at 16:20 comment added Joel David Hamkins Yes, that's right. This kind of argument arises all over computability theory.
Apr 2, 2014 at 7:14 comment added Dan Shortly, we sort all pairs $(g,h)$ and construct partial function $f$ step by step. At step $n$ we find big enough number $m$ and set $f(g_n(m)) = h_n(m) + 1$. In the end we just extend our partial function to total. Looks pretty straightforward :)
Apr 2, 2014 at 0:21 history edited Joel David Hamkins CC BY-SA 3.0
added 50 characters in body
Apr 2, 2014 at 0:10 history edited Joel David Hamkins CC BY-SA 3.0
added 259 characters in body
Apr 1, 2014 at 23:52 history edited Joel David Hamkins CC BY-SA 3.0
added 47 characters in body
Apr 1, 2014 at 23:47 history answered Joel David Hamkins CC BY-SA 3.0