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Apr 13, 2017 at 12:57 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Aug 8, 2011 at 3:03 comment added S. Carnahan I don't think closing is necessary, but it is good to note the newer question.
Aug 6, 2011 at 20:04 comment added Jean Delinez ... yes you're quite right. It's been fixed (one year later).
Aug 6, 2011 at 20:03 history edited Jean Delinez CC BY-SA 3.0
deleted 1 characters in body; edited tags
Aug 5, 2011 at 16:21 comment added Ben McKay But $CP^2$ is $SU(3)/U(2)$.
Mar 2, 2010 at 20:03 vote accept Jean Delinez
Mar 2, 2010 at 20:01 history edited Jean Delinez CC BY-SA 2.5
added 229 characters in body
Mar 1, 2010 at 23:50 answer added William Slofstra timeline score: 3
Mar 1, 2010 at 23:41 comment added William Slofstra Hmm... I'm still a little confused about your definition of the Dolbeault operator, but I'm going to post the idea that I first thought of anyway.
Mar 1, 2010 at 20:30 comment added Jean Delinez Yes, exactly.
Mar 1, 2010 at 19:00 comment added William Slofstra Are the Dolbeault operators you are referring to the usual ones defined in terms of the de Rham differential and the complex structure?
Feb 24, 2010 at 1:58 history edited Jean Delinez CC BY-SA 2.5
deleted 59 characters in body
Feb 24, 2010 at 1:34 comment added user1504 Yep. I'll check my browser. Thanks!
Feb 24, 2010 at 1:17 answer added José Figueroa-O'Farrill timeline score: 4
Feb 24, 2010 at 0:22 comment added Jean Delinez There are dollar signs around the equations and no problems on my side. Are there problems with all the equations for you?
Feb 24, 2010 at 0:17 comment added user1504 This sounds pretty cool, but I'm tired and your LaTeX didn't compile. Could you please put dollar-signs around the equations?
Feb 23, 2010 at 22:50 history asked Jean Delinez CC BY-SA 2.5