Skip to main content
10 events
when toggle format what by license comment
Mar 31, 2014 at 17:41 comment added Jason Starr @Mehdi: "You mean the Zariski open ..." Yes, indeed. Thank you for catching the typo -- it is now corrected.
Mar 31, 2014 at 17:41 history edited Jason Starr CC BY-SA 3.0
Changed D(y) to D(z)
Mar 31, 2014 at 17:16 comment added Mehdi Jason, you mean the Zariski open subset $D(zw)$?
Mar 31, 2014 at 13:55 comment added Mehdi This is a way of thinking about this problem: we can define the map $S \righarrow \mathbb{P}^1$ by $(x, y, z, w) \mapsto (x, y)$ which is defined everywhere except the finite set $\Sigma$ of the singularities of the surface $S$. This set can be blown up to yield a holomorphic map from the blowup of $S$, i.e. $g: \overline{S} \rightarrow \mathbb{P}^1$. Now if we could prove that the map $g$ can be factorized as $\overline{S} \rightarrow C \rightarrow \mathbb{P}^1$ where $C$ is a hyper elliptic curve, then we can almost prove the hyperbolicity of the surface $S$ by a standard argument.
Mar 31, 2014 at 13:54 history edited Jason Starr CC BY-SA 3.0
added 307 characters in body
Mar 31, 2014 at 13:47 comment added Mehdi Yes, Jason, I ask about the hyperbolicity of the affine surface where $zw$ is nonzero.
Mar 31, 2014 at 13:34 comment added Jason Starr Just to clarify, are you amending your question to ask about hyperbolicity of the affine surface where $zw$ is nonzero?
Mar 31, 2014 at 13:29 comment added Mehdi I guess that these are all kinds of rational curves in the surface $S$, it means that there is no rational/elliptic curve in the part $\{z\neq 0 \}\cup \{w\neq0\}$.
S Mar 31, 2014 at 11:18 history answered Jason Starr CC BY-SA 3.0
S Mar 31, 2014 at 11:18 history made wiki Post Made Community Wiki by Jason Starr