Skip to main content
6 events
when toggle format what by license comment
Oct 13, 2014 at 19:55 comment added Adam Gal One thing you can do is generalize relations by giving a function on the middle set (the one that maps to the ends) and then this corresponds to a morphim from functions on one set to functions on the other, so basically to this matrix. This can be generalized by replacing function with distribution, vector bundle, sheaf etc.
Apr 1, 2014 at 2:25 answer added Qiaochu Yuan timeline score: 4
Mar 31, 2014 at 13:10 comment added Zhen Lin The $\mathbf{Poset}$-enrichment of $\mathbf{Rel}$ is coming from the fact that $\{ 0, 1 \}$ is itself partially ordered. Perhaps you might have better luck with a (tropical) semiring instead of a field?
Mar 31, 2014 at 11:13 comment added Noam Zeilberger $\mathbf{FinMat}$ is a monoidal category, and so can be re-interpreted as a 2-category in the way you describe, but that just shifts my question one dimension up. Under that interpretation, each finite function $f : X \to Y$ determines a pair of linear transformations $k^{|X|} \to k^{|Y|}$ and $k^{|Y|} \to k^{|X|}$, and the question is whether/in what sense these can be seen as "adjoint"?
Mar 31, 2014 at 10:40 comment added Buschi Sergio you can consider vector spaces with a fixed finite base, the tensor product as arrows and linear morphisms as cells, this is a classical module's bicategory type.
Mar 31, 2014 at 7:49 history asked Noam Zeilberger CC BY-SA 3.0