Timeline for Understanding the derivation of a ML-estimator (statistics)
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 31, 2014 at 21:51 | comment | added | Brian Borchers | $(1'1)^{-1}$ is simply the scalar $1/T$. Thus $T\sigma_{c}^{2}1(1'1)^{-1}1'=\sigma_{c}^{2}11'$. | |
| Mar 31, 2014 at 16:34 | comment | added | Sunv | Sorry for the confusion. I made it clear in the buttom of the question (the original question has now been edited). | |
| Mar 31, 2014 at 12:19 | comment | added | Brian Borchers | You aren't being clear about which equality you're trying to understand. My answer gets to why $\Omega^{-1}$ is what it is. The second line of (1) reads $\Omega^{-1}=...$. Are you referring to some other equation? | |
| Mar 30, 2014 at 19:14 | vote | accept | Sunv | ||
| Mar 30, 2014 at 17:56 | vote | accept | Sunv | ||
| Mar 30, 2014 at 19:07 | |||||
| Mar 30, 2014 at 17:50 | comment | added | Sunv | Thanks for your answer. Actually I ment the second equality in the first line in (1). Do you understand what happens here? Sorry for not being clear here! | |
| Mar 30, 2014 at 17:30 | history | answered | Brian Borchers | CC BY-SA 3.0 |