Timeline for Which graphs generate a matroidal independence complex?
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 30, 2014 at 14:12 | vote | accept | Felix Goldberg | ||
| Mar 30, 2014 at 1:54 | answer | added | Richard Stanley | timeline score: 7 | |
| Mar 29, 2014 at 23:57 | vote | accept | Felix Goldberg | ||
| Mar 30, 2014 at 14:12 | |||||
| Mar 29, 2014 at 23:56 | comment | added | Felix Goldberg | Looks like I've dropped the ball on this one. Still, I think I shan't delete as perhaps this can be useful as a "don't try that" post... | |
| Mar 29, 2014 at 21:33 | answer | added | Dima Pasechnik | timeline score: 2 | |
| Mar 29, 2014 at 2:42 | comment | added | Richard Stanley | It is not true that if $G$ is well-covered, then $I(G)$ is a uniform matroid. In fact, $I(G)$ need not be a matroid complex, e.g., the complement of a 4-vertex path. | |
| Mar 28, 2014 at 22:32 | comment | added | Ricardo Andrade | Dear @Felix Goldberg, this question does not appear to be about algebraic topology. | |
| Mar 28, 2014 at 20:07 | history | asked | Felix Goldberg | CC BY-SA 3.0 |