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Oct 13, 2022 at 14:53 comment added Sidharth Ghoshal Ah so the answer for the evens is given by the euler numbers... Seems like there should be a way to analytically continue the euler numbers and end up with another interesting complex function.
Oct 13, 2022 at 2:39 comment added Sidharth Ghoshal This is very cool especially with that $2n$ in the numerator which stronlgy suggests a bridge between the riemann zeta function and alternating permutations too. Curiously where $B_{2n}$ is 0 the alternating permutation example might still be definable and that could imply the existence of "even permutation"-zeta function.
Feb 23, 2010 at 16:44 history edited David E Speyer CC BY-SA 2.5
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Feb 23, 2010 at 16:24 history answered David E Speyer CC BY-SA 2.5