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Mar 29, 2014 at 9:30 comment added Jérémy Blanc For my purpose, I only need cyclic, but you are right that finitely generated seems natural too.
Mar 29, 2014 at 9:28 comment added YCor "infinite cyclic" sounds a bit focused and unstable... the same question with "infinite finitely generated" would be more natural.
Mar 28, 2014 at 20:02 answer added Jim Humphreys timeline score: 1
Mar 28, 2014 at 11:34 answer added Venkataramana timeline score: 4
Mar 28, 2014 at 11:20 history edited Jérémy Blanc CC BY-SA 3.0
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Mar 28, 2014 at 9:49 comment added Jérémy Blanc Yes, the difficult case is when the field is infinite but countable (and I am also interested in positive characteristic by the way, but I think that this should not change the result).
Mar 28, 2014 at 8:59 comment added abx Interesting question. In characteristic 0, a linear group is unirational (this is due to Chevalley), so if $k$ is uncountable $G(k)$ must be very large. Even if $k$ is countable I would expect "too many" points, but I don't know how to get a proof from that.
Mar 28, 2014 at 7:25 history edited Jérémy Blanc CC BY-SA 3.0
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Mar 28, 2014 at 2:23 answer added user48841 timeline score: 10
Mar 27, 2014 at 23:41 history asked Jérémy Blanc CC BY-SA 3.0