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Jun 8, 2019 at 10:33 vote accept Ali Taghavi
Mar 30, 2014 at 5:01 answer added Will Sawin timeline score: 2
Mar 29, 2014 at 20:55 history edited Ali Taghavi
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Mar 27, 2014 at 17:10 comment added Gunnar Þór Magnússon Ah, of course, silly me. I still think you won't get finite-dimensional groups in general. We can maybe see that in your torus example by looking at the Fourier expansions of the coefficient functions of forms.
Mar 27, 2014 at 17:07 comment added Ali Taghavi @GunnarMagnusson in degree zero the cohomology=$\ker \phi$.. If $\alpha$ is a non vanishing 1-form, the kernel of $\phi$ is trivial, So the 0-cohomology is trvial. Am I correct?
Mar 27, 2014 at 17:07 comment added Gunnar Þór Magnússon For an $\alpha$ whose support has nonempty interior, the degree-$0$ cohomology is the space of smooth functions on $M$.
Mar 27, 2014 at 8:13 answer added Ben McKay timeline score: 5
Mar 27, 2014 at 6:20 history asked Ali Taghavi CC BY-SA 3.0