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Apr 9, 2021 at 17:19 answer added Sergio GGG timeline score: 2
Apr 14, 2016 at 2:33 answer added Lev Borisov timeline score: 2
Mar 25, 2014 at 21:34 comment added Benjamin Steinberg The answer maybe there is no answer. I was hoping for an answer not using monoids.
Mar 25, 2014 at 16:41 comment added Allen Knutson There's even a game exploiting this difficulty: en.wikipedia.org/wiki/Sylver_coinage
Mar 25, 2014 at 16:31 comment added Piotr Achinger (cont.) Note that any finite set of positive integers generates such a $P\subseteq \mathbb{N}$, but it's quite difficult to see whether two such sets generate the same monoid (see "Frobenius problem").
Mar 25, 2014 at 16:28 comment added Piotr Achinger Take a (rational polyhedral) cone $\sigma$ in $\mathbb{R}^n$ and remove a finite number of non-invertible elements of $P:=\sigma\cap \mathbb{Z}^n$. If the resulting $P'$ is a monoid (and if there are no invertible elements, you can make $P'$ a monoid by removing finitely many more elements), it gives you a non-normal affine toric variety, and all not necessarily normal affine toric varieties arise this way. I guess that pairs (cone, finite subset of integral points) is not what you're looking for. What answer would you like to have in case $P\subseteq \mathbb{N}$?
Mar 25, 2014 at 13:40 history asked Benjamin Steinberg CC BY-SA 3.0