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Oct 9, 2019 at 2:57 comment added Duchamp Gérard H. E. I only corrected a small typo in yoour beautiful answer (+1)
Oct 9, 2019 at 2:56 history edited Duchamp Gérard H. E. CC BY-SA 4.0
[unversal]--->[universal]
Mar 28, 2014 at 0:09 comment added Alexandre Eremenko @berlin: Thanks. Fortunately the book is available in our library:-)
Mar 27, 2014 at 16:20 comment added berlin @Alexandre. More on the universal property of $H(U)'$. This was known to Fantappiè in 1943 (not in this language, of course)---see the concept of Fantappiè indicatrix of an operator--- and so before the Schwartzian theory of distributions and long before Grothendieck and Schwartz developed the connection between tensor products of lcs's and operators, in particular for nuclear spaces. A succinct discussion of this and the path from the original work of Fantappiè to its incorporation into modern function analysis by the actors mentioned above is in a review by Horvath, BAMS 25 (1991) p. 162
Mar 25, 2014 at 9:23 history edited berlin CC BY-SA 3.0
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Mar 25, 2014 at 8:49 history edited berlin CC BY-SA 3.0
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Mar 25, 2014 at 8:44 history edited berlin CC BY-SA 3.0
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Mar 25, 2014 at 8:42 comment added Jochen Wengenroth The universal property of $E$ follows from Schwartz' $\varepsilon$-product (which in many cases coincides with the completed injective tensor product): $H(U,X) = H(U) \varepsilon X = L(H(U)'_{co}, X)$ where the last equality is the definition and $F'_{co}$ is the dual of the locally convex space $F$ endowed with uniform convergence on all absolutely convex compact sets. Since $H(U)$ is a Montel space, in our case this is the same as the strong dual of $H(U)$.
Mar 25, 2014 at 8:30 history edited berlin CC BY-SA 3.0
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Mar 24, 2014 at 22:45 comment added Alexandre Eremenko berlin: could you give a more precise reference, for non-specialists on topological vector spaces, on the a) existence proof of such $E$ and b) that the dual of $H(U)$ has this property ?
Mar 24, 2014 at 21:13 history answered berlin CC BY-SA 3.0