Timeline for Must a closed totally path-disconnected subset of the sphere have connected complement?
Current License: CC BY-SA 3.0
10 events
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
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| Mar 24, 2014 at 14:55 | vote | accept | user126154 | ||
| Mar 24, 2014 at 14:50 | history | edited | Ricardo Andrade | CC BY-SA 3.0 |
removed deprecated tag 'topology'; minor corrections; reworded title
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| Mar 24, 2014 at 14:18 | answer | added | Eric Wofsey | timeline score: 10 | |
| Mar 24, 2014 at 13:07 | comment | added | user126154 | Sorry I realized that I stated badly question 1) | |
| Mar 24, 2014 at 13:07 | history | edited | user126154 | CC BY-SA 3.0 |
Edit to correctly state question 1)
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| Mar 24, 2014 at 13:05 | comment | added | user126154 | I don't know it there is standard terminology. I would say that A is totally path disconnected if every continuous function $[0,1]\to A$ is constant. | |
| Mar 24, 2014 at 13:00 | comment | added | Mirko | What do totally path connected and totally path disconnected mean? Totally disconnected according to Engelking's General topology means for each $x$ the quasi-component (= intersection of all clopen sets containing $x$) is $\{x\}$. Please include definitions or a reference. | |
| Mar 24, 2014 at 12:48 | history | asked | user126154 | CC BY-SA 3.0 |