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Feb 26, 2010 at 17:38 comment added Joel David Hamkins Henry, I had had the same thought, and I have asked a question at mathoverflow.net/questions/16532 following up on this.
Feb 23, 2010 at 17:27 comment added HJRW There's still a reasonable question in that area. For instance, you could restrict yourself to perfect groups.
Feb 23, 2010 at 14:18 vote accept Chad Groft
Feb 23, 2010 at 12:05 comment added Joel David Hamkins +1. Very good. It's too bad we can't have Rice's theorem here...
Feb 23, 2010 at 4:46 comment added Chad Groft Yes, you're absolutely right. More generally, any property of G that is computable from the isomorphism type of ab(G) is computable from a finite presentation for G.
Feb 23, 2010 at 4:34 history answered John Stillwell CC BY-SA 2.5