Timeline for How does the inverse mean curvature flow start with minimal surface?
Current License: CC BY-SA 3.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 29, 2014 at 6:54 | vote | accept | Jer | ||
| Mar 24, 2014 at 8:33 | comment | added | Jer | If the initial hypersurface for inverse mean curvature flow is the minimal surface, the penrose inequality could be proved with the monotonicity of the Hawking mass. I am a little confused about the beginning of the flow and want to understand that more clearly. | |
| Mar 23, 2014 at 20:58 | history | edited | Ben McKay | CC BY-SA 3.0 |
fixed formatting, grammar
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| Mar 23, 2014 at 17:39 | answer | added | Otis Chodosh | timeline score: 6 | |
| Mar 23, 2014 at 17:36 | review | First posts | |||
| Mar 23, 2014 at 17:37 | |||||
| Mar 23, 2014 at 17:24 | comment | added | Ben McKay | Why do you believe that the flow starts at such a point or for a minimal surface? | |
| Mar 23, 2014 at 17:17 | history | asked | Jer | CC BY-SA 3.0 |