Timeline for A linear consequence of the Michael selection theorem
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Mar 24, 2014 at 7:33 | comment | added | Jochen Wengenroth | There are always a continuous selection and linear selection (playing with Hamel bases) but of course not always a continuous linear one. | |
| Mar 23, 2014 at 1:19 | history | edited | Ali Taghavi |
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| Mar 23, 2014 at 1:11 | vote | accept | Ali Taghavi | ||
| Mar 23, 2014 at 0:45 | answer | added | Mirko | timeline score: 2 | |
| Mar 23, 2014 at 0:33 | comment | added | Yemon Choi | See math.stackexchange.com/questions/411119/… | |
| Mar 23, 2014 at 0:27 | comment | added | Yemon Choi | The title is not very apt: the previous comment explains why. Your question is equivalent to: "is a closed subspace of a Banach space always complemented?" and the answer is "usually no". | |
| Mar 23, 2014 at 0:22 | comment | added | Mirko | Would the following be an answer? There is no bounded linear 1-1 mapping $\ell^\infty/c_0 \to \ell^\infty$ Corollary 20 in link | |
| Mar 22, 2014 at 23:34 | history | edited | Ali Taghavi | CC BY-SA 3.0 |
added 7 characters in body
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| Mar 22, 2014 at 23:17 | history | asked | Ali Taghavi | CC BY-SA 3.0 |