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Jun 22, 2022 at 8:13 history edited CommunityBot
replaced http://math.uga.edu/~pete with http://alpha.math.uga.edu/~pete
Feb 22, 2010 at 14:50 comment added Tyler Lawson If it is an open subset if $\mathbb{A}^n$, then they are birational and you can use extensions of $\mathbb{A}^n$ that introduce a common nontrivial extension of their function fields.
Feb 22, 2010 at 14:36 comment added David E Speyer Regarding the question of finding a simply connected affine variety (of positive dimension): I'm tempted to say that it is not possible. Embed $X$ into $\mathbb{A}^n$ and take a nontrivial cover of $\mathbb{A}^n$ to get a nontrivial cover of $X$. The gap in this argument, of course, is that the cover of $X$ might not be connected. Any idea how to get around this?
Feb 22, 2010 at 12:54 history edited Pete L. Clark CC BY-SA 2.5
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Feb 22, 2010 at 12:46 history edited Pete L. Clark CC BY-SA 2.5
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Feb 22, 2010 at 12:17 history answered Pete L. Clark CC BY-SA 2.5