Timeline for Would such polynomial identity exist? (related to sum of four squares)
Current License: CC BY-SA 3.0
5 events
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Mar 12, 2014 at 17:05 | history | edited | Sasha | CC BY-SA 3.0 |
added 17 characters in body
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Mar 12, 2014 at 17:03 | comment | added | Sasha | You are right, sorry. | |
Mar 12, 2014 at 16:46 | comment | added | Achim Krause | You somehow assume that $f_5$ has a rational root, whereas in general a nonconstant polynomial can very well be irreducible over Q. Joro's example works perfectly well, since $x^2+3$ only has complex roots. | |
Mar 12, 2014 at 16:35 | comment | added | joro |
Thanks what do you mean by any degree? I get (3-x^2)^2+(2*x)^2+(2*x)^2+(2*x)^2=(x^2+3)^2
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Mar 12, 2014 at 16:22 | history | answered | Sasha | CC BY-SA 3.0 |