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Oct 8, 2014 at 15:41 comment added Fedor Petrov Do yo need implicit sequence? I guess, Markov process produces a lot of such sequence: for $p=p_{00}/(p_{00}+p_{01})$, $q=p_{10}/(p_{10}+p_{11})$ define $x_{n+1}=0$ or $x_{n+1}=1$ with probabilities $p$ and $1-p$ if $x_n=0$; $x_{n+1}=0$ or $x_{n+1}=1$ with probabilities $q$ and $1-q$ if $x_n=1$.
Oct 8, 2014 at 15:07 history edited Ian Morris
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Mar 12, 2014 at 10:08 answer added Roland Bacher timeline score: 1
Mar 11, 2014 at 15:04 history asked Kan CC BY-SA 3.0