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Mar 10, 2014 at 16:20 comment added Peter Dukes Sorry. My "whenever" was an unclear way of quantifying over all such perturbations. I realize I discussed $\widehat{A}$ before $\epsilon$, but I meant for $\epsilon$ to depend on $A$ only. So in particular $\epsilon \le \lambda_n$. I'll adjust my question. (Still, your answer is helpful... thanks!)
Mar 10, 2014 at 14:44 history edited user39115 CC BY-SA 3.0
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Mar 10, 2014 at 14:16 history answered user39115 CC BY-SA 3.0