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Mar 12, 2014 at 19:50 vote accept Ludolila
Mar 12, 2014 at 4:49 comment added Ali Taghavi @Ludolila In fact we do not need to "rotation number". We need only to lift a homeomorphism $f$ of $S^{1}$ to a homeomorphism $F$ of $R$. This statment is written in the first line after the definition of the above link
Mar 10, 2014 at 8:34 comment added Ludolila Thank you! The truth is, I am not very familiar with these methods, though I do encounter the notion of rotation number every once in a while. I thought that maybe there is a more set-theoretic topological approach?
Mar 9, 2014 at 19:44 history edited Ali Taghavi CC BY-SA 3.0
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Mar 9, 2014 at 19:24 history edited Ali Taghavi CC BY-SA 3.0
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Mar 9, 2014 at 19:08 history answered Ali Taghavi CC BY-SA 3.0