Timeline for Two questions on isometric embedding
Current License: CC BY-SA 3.0
13 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:58 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| Mar 9, 2014 at 22:30 | answer | added | Deane Yang | timeline score: 4 | |
| Mar 9, 2014 at 18:29 | answer | added | John Pardon | timeline score: 4 | |
| Mar 9, 2014 at 18:01 | history | edited | Ricardo Andrade | CC BY-SA 3.0 |
added top level tag; minor reformatting and corrections
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| Mar 9, 2014 at 17:46 | answer | added | Misha | timeline score: 2 | |
| Mar 9, 2014 at 14:32 | comment | added | ThiKu | Right, I just noticed immediately after sending. | |
| Mar 9, 2014 at 14:31 | comment | added | Ali Taghavi | @user39082 an isometric embedding does not necessarily send geodesic to geodesic. | |
| Mar 9, 2014 at 14:29 | comment | added | ThiKu | But ... how does this fit with Degtyarev's example? | |
| Mar 9, 2014 at 14:26 | comment | added | ThiKu | By Nash's Theorem there is an isometric embedding of M into some euclidean space. It can be chosen $C^2$ (even $C^\infty$) so geodesics must be sent to geodesics in euclidean space, that is straight lines. | |
| Mar 9, 2014 at 14:12 | history | edited | Ali Taghavi |
edited tags
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| Mar 9, 2014 at 13:55 | history | edited | Ali Taghavi | CC BY-SA 3.0 |
deleted 2 characters in body
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| Mar 9, 2014 at 13:49 | history | edited | Ali Taghavi | CC BY-SA 3.0 |
added 2 characters in body
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| Mar 9, 2014 at 13:30 | history | asked | Ali Taghavi | CC BY-SA 3.0 |