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Aug 26, 2015 at 16:25 comment added abx In the case $S=\mathrm{Spec}\mathbb{C}$ I think bijectivity is enough: since $G$ acts transitively $X$ is normal, and a bijective map of normal varieties is an isomorphism (in char. $0$).
Aug 26, 2015 at 13:54 comment added Brenin Hi @abx! In the torsor condition that you quote, you really mean isomorphism of schemes, or is it enough to have a bijection on closed points? (let us say $S=\textrm{Spec }\mathbb C$ for simplicity) Thanks in advance!
Mar 6, 2014 at 12:50 history edited ACL CC BY-SA 3.0
Completing reference
Mar 6, 2014 at 11:08 history answered abx CC BY-SA 3.0